Question

What is the equation in point-slope form of the line that passes through the points (7, 5) and (−4, −1) ?


y+1=611(x+4)

y−1=611(x−4)

y+4=116(x+1)

y+1=67(x+4)

Answer 1

Answer:

A

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (7, 5) and (x₂, y₂ ) = (- 4, - 1)

m = $\frac{-1-5}{-4-7}$ = $\frac{-6}{-11}$ = $\frac{6}{11}$

Use either of the 2 points for (a, b)

Using (a, b) = (- 4, - 1), then

y - (- 1) = $\frac{6}{11}$(x - (- 4)), that is

y + 1 = $\frac{6}{11}$(x + 4)  ← first option