Question

A motorist is traveling at a constant velocity of v = 13.0 m/s and passes a school-crossing corner where the speed limit is 10 m/s (about 22 mi/h). A police officer on a motorcycle stopped at the corner then starts off in pursuit with a constant acceleration of a = 5.00 m/s2. Calculate the positions of the police officer and the car at the moment when they have the same velocity.

Answer 1

Answer:

Position of motorist = 33.8 m

position of police officer = 16.9 m

Explanation:

velocity of motorist, v = 13 m/s

initial velocity of police officer, u = 0

Acceleration of police officer, a = 5 m/s^2

let after time t, the velocity of police officer is equal to the velocity of motorist.

v = u + at

13 = 0 + 5 t

t = 2.6 second

Position of motorist after 2.6 second = v x t = 13 x 2.6 = 33.8 m

Position of police officer after t = 2.6 s

s = ut + 0.5 at^2

s = 0 + 0.5 x 5 x 2.6 x 2.6 = 16.9 m