Answer:
[tex]Lenght=110\ m\\Width=35\ m[/tex]
Step-by-step explanation:
The area of a rectangle can be calculated with this formula:
[tex]A=lw[/tex]
Where "l" is the lenght and "w" is the width.
In this case,based on the data given in the exercise, we know that:
[tex]l=3w+5\\\\A=3,850[/tex]
Then, we can make the substitution into the formula [tex]A=lw[/tex]:
[tex]3,850=(3w+5)w[/tex]
Simplifying:
[tex]3w^2+5w-3,850=0[/tex]
Now we can apply the Quadratic formula [tex]w=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex].
In this case:
[tex]a=3\\b=5\\c=-3,850[/tex]
Substituting these values into the formula, we get:
[tex]w=\frac{-5\±\sqrt{5^2-4(3)(-3,850}}{2(3)}\\\\\\w_1=-36.66\\\\w_2=35}[/tex]
Since the width cannot be negative:
[tex]w=35\ m[/tex]
Substituting the width into [tex]l=3w+5[/tex], we get:
[tex]l=3(35)+5\\\\l=110\ m[/tex]