A huge suspended LED screen is the centerpiece of The Place, a popular mall in Beijing, China. Find the length and width of a similar rectangular screen if the length is 5 meters more than 3 times its width, and the viewable area is 3,850 square meters.

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Answer:

[tex]Lenght=110\ m\\Width=35\ m[/tex]

Step-by-step explanation:

The area of a rectangle can be calculated with this formula:

[tex]A=lw[/tex]

Where "l" is the lenght and "w" is the width.

In this case,based on the data given in the exercise, we know that:

[tex]l=3w+5\\\\A=3,850[/tex]

Then, we can make the substitution into the formula [tex]A=lw[/tex]:

[tex]3,850=(3w+5)w[/tex]

Simplifying:

[tex]3w^2+5w-3,850=0[/tex]

Now we can apply the Quadratic formula [tex]w=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex].

In this case:

[tex]a=3\\b=5\\c=-3,850[/tex]

Substituting these values into the formula, we get:

[tex]w=\frac{-5\±\sqrt{5^2-4(3)(-3,850}}{2(3)}\\\\\\w_1=-36.66\\\\w_2=35}[/tex]

Since the width cannot be negative:

[tex]w=35\ m[/tex]

Substituting the width into [tex]l=3w+5[/tex], we get:

[tex]l=3(35)+5\\\\l=110\ m[/tex]

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