The dimensions of the closed rectangular box are 14 by 14 by 14
Step-by-step explanation:
Volume of the box will be : l×w×h but l=w,hence volume= w²h
Area of the box is : 2w² + 4hw
Volume,v=w²h=2744----------find height,h
h=2744/w²-------------use this height in the area equation as;
Area=2w²+4hw
[tex]A=2w^2+4(\frac{2744}{w^{2} } )*w\\\\\\A=2w^2+\frac{10976}{w} \\[/tex]
Minimizing the area
[tex]dA/dw=4w-10976/w^2\\\\\\4w-10976/w^2=0\\\\\\4w^3-10976=0\\\\4w^3=10976\\\\w^3=2744\\\\w=\sqrt[3]{2744}\\ \\\\w=14[/tex]
w=15,to find the height use h=2744/w²
h=2744/14²
h=14
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Volume of a rectangular box :https://brainly.com/question/1414246
Keywords : volume
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