Answer:
Step-by-step explanation:
Let X be the number of tickets issued by a meter reader for parking-meterviolations can be modeled by a Poisson process with a rateparameter of five per hour.
X is Poisson with parameter =5per hour
a) the probabilitythat exactly three tickets are given out during a particular hour
=[tex]P(X=3)=0.14037[/tex]
b) the probabilitythat at least three tickets are given out during a particularhour
=[tex]P(X\geq 3) =0.87534[/tex]
c) tickets we expect to be given during a 45-min period
=[tex]5(\frac{3}{4} )\\= 3.75[/tex]
Note: Poisson distribution is
[tex]P(X=k) = \frac{e^{-k} 5^k}{l!}[/tex]
