at a supermarket , Monica paid 3.20 for 2 pounds of apples and 2 pounds of oranges, while Sarah paid 4.40 for 2 pounds of apples and 4 pounds of oranges. At these rates, what is the cost , in dollars, for 3 pounds of oranges?

Respuesta :

The cost , in dollars, for 3 pounds of oranges is 1.8

Solution:

Given that Monica paid 3.20 for 2 pounds of apples and 2 pounds of oranges

Sarah paid 4.40 for 2 pounds of apples and 4 pounds of oranges.

Let the cost of orange per pound = x  

Let the cost of apple per pound = y  

Therefore, we can frame an equation as follows for Monica and Sarah:

In Monica’s case:  

2x + 2y = 3.20  

Hence x + y = 1.6 ---- eqn 1

In Sarah’s case:  

4x + 2y = 4.40  

Hence 2x + y = 2.2

y = 2.2 -2x – eqn 2

Substitute eqn 2 in eqn 1 we get,

x + 2.2 -2x = 1.6

-x = 1.6-2.2 = -0.6

x = 0.6

Substituting the value of “x” in eqn 2 we get the value of “y” as 1

Thus the cost of orange per pound is 0.6

Therefore, cost of 3 pounds of oranges = 3 × 0.6 = 1.8

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