Respuesta :
Answer:
v = 80.092 m/s
a = 15.945 m/s²
Explanation:
Given,
The distance completed by the dragster, d = 402.3 m
The time taken by the dragster to complete that distance is, t = 5.023 s
The initial velocity of the dragster, u = 0
The final velocity of the dragster, v = ?
The acceleration of the dragster, a = ?
The velocity of the body is given by the formula
v = d/t m/s
Substituting the above values inn the equation
v = 402.3 m / 5.023 s
= 80.092 m/s
So, the velocity of the dragster is, v = 80.092 m/s
The acceleration of the body is given by the formula
a = (v - u)/t m/s²
Substituting the above values in the equation
= (80.092 - 0) / 5.023
= 15.945 m/s²
Hence, the acceleration of the dragster is, a = 15.945 m/s²
The dragster car which runs with the constant acceleration, has acceleration 15.954 m/s² and has final velocity 80.092 m/s.
What is velocity of a object?
Velocity of a object is the ratio of distance traveled by the object with the time taken.
[tex]v=\dfrac{s}{t}[/tex]
Here, (s) is the displacement of the body and (t) is the time taken by it.
The dragster completed a 402.3 run in 5.023s. Thus, the total distance covered by the dragster is 402.3 m and the total time taken by it to cover this distance is 5.023 seconds.
Use the above formula to find the velocity as,
[tex]v=\dfrac{402.3}{5.023}\\v=80.092\rm\;m/s[/tex]
Acceleration of a body is the change in velocity of the body with respect to the time. As the initial velocity of the car is zero. Thus,
[tex]a=\dfrac{80.092-0}{5.023}\\a=15.954\rm \;m/s^2[/tex]
Hence, the dragster car which runs with the constant acceleration, has acceleration 15.954 m/s² and has final velocity 80.092 m/s.
Learn more about the velocity here;
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