Answer:
The dimensions of the enlargement picture are 28 1/8 inches width and 16 7/8 inches length
Step-by-step explanation:
we know that
To find out the dimensions of the enlargement, multiply the original size by the scale factor
we have
The scale factor is 4 1/2
Original size of the picture are 6 1/4 in width, 3 3/4 inches length
step 1
Convert mixed number to an improper fraction
[tex]4\frac{1}{2}=\frac{4*2+1}{2}=\frac{9}{2}[/tex]
[tex]6\frac{1}{4}\ in=\frac{6*4+1}{4}=\frac{25}{4}\ in[/tex]
[tex]3\frac{3}{4}\ in=\frac{3*4+3}{4}=\frac{15}{4}\ in[/tex]
step 2
Find out the dimensions of the enlargement
Width
[tex]\frac{9}{2}(\frac{25}{4})=\frac{225}{8}\ in[/tex]
Convert to mixed number
[tex]\frac{225}{8}\ in=\frac{224}{8}+\frac{1}{8}=28\frac{1}{8}\ in[/tex]
Length
[tex]\frac{9}{2}(\frac{15}{4})=\frac{135}{8}\ in[/tex]
Convert to mixed number
[tex]\frac{135}{8}\ in=\frac{128}{8}+\frac{7}{8}=16\frac{7}{8}\ in[/tex]
therefore
The dimensions of the enlargement picture are 28 1/8 inches width and 16 7/8 inches length