Question

find the 16 term in sequence a(n) = -6+3(n-1)

Answer 1

39. A(16) = -6 + 3(16-1) = -6 + 45 = 39.

Answer 2

Answer:

16th term in sequence a(n) = -6+ (n-1) 3 is 39.

Solution:

Need to determine 16 terms in sequence.

a(n) = -6+3(n-1) that is $a_n$ = -6+ (n-1) 3

from given expression we can say that first term $a_1$ = -6 and common difference d = 3

And given expression $a_n$ = -6+ (n-1) 3 represents formula of nth term of an Arithmetic Sequence.  

So substituting n = 16 in given formula we get  

$a_{16}$ = -6+ (16-1) 3

=> $a_{16}$ = -6 + (15 x 3)  

=> $a_{16}$ = -6 + 45  

=> $a_{16}$ = 39

Hence 16th term in sequence $a_n$ = -6+ (n-1) 3 is 39.