Question

how to solve this equation 6x^2-2x+5+2x^2-7x-11

Answer 1

x= $\frac{9+\sqrt{273} }{16}$

OR

x= $\frac{9-\sqrt{273} }{16}$

Step-by-step explanation:

The given equation is

$6x^{2}$-2x+5+$2x^{2}$-7x-11

Step 1: Arrange the equation

$6x^{2}$+$2x^{2}$-2x-7x-11+5

Step 2: Simplify the equation

$8x^{2}$-9x-6

Step 3: Identify a,b,c in the equation

a=8

b=-9

c=-6

Step 4: Apply quadratic formula to find the possible values of x

x = $\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

x= $\frac{-(-9)±\sqrt{(-9)^{2}-4(8)(-6) } }{2(8)}$

x= $\frac{9+\sqrt{273} }{16}$

OR

x= $\frac{9-\sqrt{273} }{16}$

Keyword: Equation

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