Answer:
1) a = 3.2 m/s²
2) d = 160 m
3) d = 30 m
Explanation:
1) Given,
The initial velocity of the car, u = 0
The final velocity of the car, v = 32 m/s
The time taken to complete the trip is, t = 10 s
The acceleration of the car is,
a = (v - u) / t
= (32 - 0) / 10
= 3.2 m/s²
The constant acceleration of the car is, a = 3.2 m/s²
2) The total distance covered by the car is given by
d = vₐ x t
= 16 x 10 ∵ Average velocity = (32 - 0)/2
= 160 m
Hence, the total distance covered by the car is, d = 160 m
3) Given,
The initial velocity of the jogger, u = 0
The final velocity of the jogger, v = 6 m/s
The time taken by the jogger to reach the final velocity is, t = 10 s
The distance covered by the jogger,
d = vₐ x t
= 3 x 10 ∵ vₐ is the average velocity
= 30 m
Hence, the distance covered by the jogger is, d = 30 m
