Answer:
-5.649065 and -0.942935
Step-by-step explanation:
The degree of freedom will be given by
n - 1 where n is the sample number, given here as 15 so
[tex]D_f=15-1=14[/tex]
Critical time, t for a 95% confidence interval from the table is
[tex]t_{crit} = 2.145[/tex]
The 95% confidence levels will be given by
Limit=Parameter estimate ± Critical t * standard error of parameter estimate.
The standard error of parameter estimate is given as 1.097
First limit=-3.296 -( 2.145*1.097 )= -5.649065
Second limit = -3.296 + (2.145*1.097) = -0.942935