Respuesta :

Answer:

0.507 L or 507 cm³

Explanation:

Given,

Initial Volume, V1 = 475 cm³or 0.475 L

Initial temperature, T1 = 25 °C or 298.15 K (since, K = °C + 273.15)

Final temperature, T₂ = 45°C or 318.15 K

We can calculate the new volume;

Using the concept of Charles' law ;

[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]

Therefore,

To get, V2, we use;

[tex]V2=\frac{V1T2}{T1}[/tex]

[tex]V2=\frac{(0.475L)(318.15K)}{298.15K}[/tex]

[tex]V2=0.507L[/tex]

Thus, the gas would expand to a volume of 0.507 L or 507 cm³ to maintain the same pressure.

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