0.507 L or 507 cm³
Given,
Initial Volume, V1 = 475 cm³or 0.475 L
Initial temperature, T1 = 25 °C or 298.15 K (since, K = °C + 273.15)
Final temperature, T₂ = 45°C or 318.15 K
We can calculate the new volume;
Using the concept of Charles' law ;
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]
Therefore,
To get, V2, we use;
[tex]V2=\frac{V1T2}{T1}[/tex]
[tex]V2=\frac{(0.475L)(318.15K)}{298.15K}[/tex]
[tex]V2=0.507L[/tex]
Thus, the gas would expand to a volume of 0.507 L or 507 cm³ to maintain the same pressure.