Answer:
91.1835 nm
Explanation:
Given that the ionization energy of the oxygen molecule = 1314 kJ/mol
It means that
1 mole of oxygen molecules can be ionized by the energy = 1314 kJ = 1314000 J
1 mole of molecules contains 6.022 × 10²³ atoms
So,
6.022 × 10²³ atoms of oxygen molecules can be ionized by the energy = 1314000 J
1 atom require [tex]\frac{1314000}{6.022\times 10^{23}}\ J[/tex] of energy
Energy = [tex]2.18\times 10^{-18}\ J[/tex]
Also
[tex]E=\frac {h\times c}{\lambda}[/tex]
Where,
h is Plank's constant having value [tex]6.626\times 10^{-34}\ Js[/tex]
c is the speed of light having value [tex]3\times 10^8\ m/s[/tex]
[tex]\lambda[/tex] is the wavelength
So,
[tex]\lambda=\frac {h\times c}{E}[/tex]
[tex]\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{2.18\times 10^{-18}}\ m[/tex]
[tex]\lambda=91.1835\times 10^{-9}}\ m[/tex]
Also,
[tex]1\ nm=10^{-9}}\ m[/tex]
So, wavelength = 91.1835 nm