Answer:
The weight of pure gold in 258 g rams of 18- karat gold is 193.5 grams.
Step-by-step explanation:
The pure percentage in the gold = 75%
The weight of the gold purchased = 258 g
Now, here the pure gold percentage is 75% of 258 g
75% of 258 grams = [tex]\frac{75}{100} \times 258[/tex]
or, [tex]\frac{3}{4} \times 258 = 193.5[/tex]
⇒75% of 258 grams = 193.5 grams
Hence, the weight of pure gold in 258 g rams of 18- karat gold is 193.5 grams.
