Answer:
[tex]\large \boxed{m = -\frac{1}{2};\text{ y-intercept = 2}}}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation is
y = mx + b, where
m = the slope and
b = the y-intercept
We must solve your equation for y.
It will then be in the slope-intercept form.
[tex]\begin{array}{rcll}3x + 6y & = & 12 & \\6y & = & 12 - 3x & \text{Subtracted 3x from each side}\\y&= &2 -\frac{1}{2}x& \text{Divided each side by 3}\\\mathbf{y} &= & \mathbf{-\frac{1}{2}x + 2}& \text{Rearranged terms}\\\end{array}\\\\\large \boxed{\mathbf{m = -\frac{1}{2};\textbf{y-intercept = 2}}}[/tex]
The diagram below shows the equation of your graph with m = -½ and the y-intercept at (0, 2)
