As per given , we have
[tex]H_0: p\leq\dfrac{3}{4}\\\\H_a: p>\dfrac{3}{4}[/tex]
Since , alternative hypothesis is right tailed, so the test is a right tailed test.
n= 1987
Proportion of adults believe that rudeness is a worsening problem : [tex]p=\dfrac{1257}{1987}\approx 0.6326[/tex]
Test statistic : [tex]z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}[/tex]
[tex]z=\dfrac{ 0.6326-0.75}{\sqrt{\dfrac{0.75(1-0.75)}{1987}}}=-12.09[/tex]
(since , the normal curve takes values of z from -7 to 7, so we use critical value to draw conclusion.)
The critical value for a significance level of 0.005= 1.645
Since , absolute test statistic value (12.09) is greater than the critical value (1.645), it means there is statistical significance and so we reject the null hypothesis.