Answer:
The solution to the system of equations 4x−3y=26 and 3x+2y=11 is x=5 and y= -2
Solution:
Given that two linear equations are 4x−3y=26 and 3x+2y=11
We have to find the values of “x” and “y”
Let us consider 4x−3y=26 ---- eqn 1
3x+2y=11 --- eqn 2
Multiplying equation 1 with 2 we get,
8x – 6y = 52 --- eqn 3
Similarly multiplying equation 2 with 3 we get,
9x + 6y = 33 --- eqn 4
Solving equation 3 and equation 4 we get,
17x + 0 = 85
17x = 85
x = 5
Substitute the value of “x” in equation1 to get “y” value,
4(5) – 3y = 26
20 – 3y = 26
3y = 20-26
y = -2
Hence the solution to the system of equations 4x−3y=26 and 3x+2y=11 is x=5 and y= -2
