Question

Simplify. 5x^3/(7x^3+x^4)
5/7+x; where x is not equal to 0, -7
5/7+x; where x is not equal to -7
5/7x; where x is not equal to 0
5/7

Answer 1

Hello,

$\frac{5 x^{3} }{7 x^{3} + x^{4} } = \frac{5 x^{3} }{x^{3}(7+x) }=\frac{5} {7+x}$

Answer Almost A with parenthesis 

5/(7+x)