Answer:
The correct answer is B. water will leave the balloon.
Explanation:
As the sucrose concentration is higher in the solution, the water in the balloon, where the sucrose is less concentrated, will tend to leave and try to dilute the outer solution until both sucrose concentrations are equal. But as the water leaves the balloon, the concentration inside will increase, so it will flow outside until both concentrations are equal and not until the outer concentration is similar to the initial concentration in the balloon.
