What is the equation on point slope form of a line that passes through the point -4, - 1 and 5, 7

Answer:
The equation of the line is c) [tex]( y+1) = \frac{8}{9} ( x+4)[/tex]
Step-by-step explanation:
Here, the two points are (x1, y1) = (-4,-1) and (x2, y2)= (5,7)
So, the slope of the line joining two points [tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Here, [tex]m = \frac{7 - (-1)}{5 - (-4)} = \frac{8}{9}[/tex]
Also, by POINT SLOPE formula line equation is:
(y - y0) = m (x - x0) ; here m = slope and (x0, y0) is a point on line
So, here the equation of line is:
[tex](y - (-1)) = \frac{8}{9} ( x-(-4))\\or, ( y+1) = \frac{8}{9} ( x+4)[/tex]
Hence,the equation of the line is c) [tex]( y+1) = \frac{8}{9} ( x+4)[/tex]