Answer:
a) 1/2
b) 3/5
c) 1/5
Step-by-step explanation:
[tex]f(x)=\frac{1}{(b-a)} , a\leq x\leq b; E(X)=\frac{a+b}{2}[/tex]
and [tex]Sigma^{2} =\frac{(b-a)^{2} }{12}[/tex]
X ~ Uniform(9,12),
[tex]f(x)=\frac{1}{b-a}=\frac{1}{12-9}=\frac{a}{3} , 9\leq x\leq 12[/tex]
a) [tex]p(x\leq 10.5)=\int\limits^a_b {\frac{1}{3} } \, dx =\frac{10.5-9}{3}=\frac{1}{2}[/tex]
Where b = 9 and a = 10.5
b) [tex]p(9.4\leq x\leq 11.2)=\int\limits^a_b {\frac{1}{3} } \, dx =\frac{11.2-9.4}{3}=\frac{3}{5}[/tex]
Where b = 9.4 and a = 11.2
c) [tex]p(x\geq 11.4)=\int\limits^a_b {\frac{1}{3} } \, dx =\frac{12-11.4}{3}=\frac{1}{5}[/tex]
Where b = 11.4 and a = 12