Question

a man is standing on the edge of a 20.0m high cliff. he throws a rock vertically with an initial velocity of 10.0m/s. how high does the rock go?​

Answer 1

Answer:5m

Explanation:a=-10m/s (since it moved upwards against gravity)

V=0

U=10m/s

v2=u2+2as

0= 100-20s

20s=100

s=5m