Answer:
[tex]v_{1i} = 6 m/s[/tex]
Explanation:
Here we know that the whole system is having no external force on it
So the total momentum of the system will remain conserved
So here we can say
[tex]m_1v_{1i} + m_2v_{2i} = (m_1 + m_2) v_f[/tex]
here we have
[tex]m_1 = 5000 kg[/tex]
[tex]m_2 = 10,000 kg[/tex]
[tex]v_{2i} = 0[/tex]
[tex]v_f = 2 m/s[/tex]
now we have
[tex]5000(v_{1i}) + 0 = (5000 + 10000) (2)[/tex]
[tex]v_i = \frac{15000}{5000}(2)[/tex]
[tex]v_{1i} = 6 m/s[/tex]