Answer:
C. Decreases the margin of error and hence increases the precision
Step-by-step explanation:
If we select a sample by Simple Random Sampling in a population of “infinite” size (a population so large that we do not know its size exactly), then the margin of error is given by
[tex]\bf E=\frac{ZS}{\sqrt{n}}[/tex]
where
Z = The Z-score corresponding to the confidence level
S = The estimated standard deviation of the population
n = the size of the sample.
As we can see, since n is in the denominator of the fraction and the numerator is kept constant, the larger the sample size the smaller the margin of error, so the correct choice is:
C. Decreases the margin of error and hence increases the precision