Answer:
0.00245 moles of HCl
Explanation:
We are given;
Volume of KOH = 9.71 mL
Molarity of KOH = 0.252 M
Volume of HCl = 15.0 mL
We are required to determine the number of moles of HCl
Step 1: Write the balanced equation for the reaction
The reaction between HCl and KOH is given by;
KOH(aq) + HCl(aq) → KCl(aq) + H₂O(l)
Step 2: Calculating the number of moles of KOH
Molarity = Moles ÷ Volume
Rearranging the formula;
Moles = Molarity × Volume
= 0.252 M × 0.00971 L
= 0.00245 moles
Step 3: Moles of HCl
From the equation, 1 mole of KOH reacts with 1 mole of HCl
Therefore, the mole ratio of KOH : HCl is 1 : 1
Thus,
Moles of HCl will be 0.00245 moles
Therefore, there are 0.00245 moles of HCl in the solution.
