Answer:
[tex]\textbf{$P(S \cap T) = \frac{89}{90}$ }\\[/tex]
Step-by-step explanation:
[tex]\textup{Mutually events are events that cannot occur at the same time.}\\\textup{When you toss a coin you get only $head$ or only $tail$ but never both.}\\ \textup{In mathematical terms $P(A) \cup P(B) = 0$, where $A$ and $B$ are mutually exclusive events. }\\\textup{We know the formula:}\\$ P(A \cup B) = P(A) + P(B) - P(A \cup B) $\\\textup{When $A$ and $B$ are mutually exclusive, it will simply be:}\\$ P(A \cup B) = P(A) + P(B) $\\\textup{Now given:}\\ $P(S) = 8/9$ , $P(T) = 1/10$\\[/tex]
[tex]$ \implies P(S \cup T) = \frac{89}{10}$[/tex]
