Question

What is the quotient (125 – 8x3) ÷ (25 + 10x + 4x2)?
–2x + 5
2x – 5
–2x – 5
2x + 5

Answer 1

If you would like to solve (125 - 8x^3) / (25 + 10x + 4x^2), you can do this using the following steps:

(125 - 8x^3) / (25 + 10x + 4x^2) = - ((2x - 5) * (4x^2 + 10x + 25)) / (4x^2 + 10x + 25) = - (2x - 5) = - 2x + 5

The correct result would be - 2x + 5.

Answer 2

For this case we have the following expression:

$\frac{125-8x^3}{25+10x+4x^2}$

Factoring the numerator we have:

$\frac{-(2x+5)(4x^2+10x+25)}{25+10x+4x^2}$

Rewriting the denominator we have:

$\frac{-(2x+5)(4x^2+10x+25)}{4x^2+10x+25}$

Canceling similar terms we have:

$-(2x+5)$

$-2x-5$

Answer:

The quotient of the division is given by:

$-2x-5$