Answer:
The solution of |x-1| = 5x + 2 is [tex]x = \frac{-1}{6}[/tex] and option c is correct.
Solution:
Given, equation is |x-1|= 5x + 2
We have to find the value of x
Now, |x-1|= 5x + 2
Because mod becomes "±" when shifted to opposite side of “=”
x – 1 = ±(5x+2)
x – 1 = 5x + 2 or x – 1 = -(5x + 2)
[tex]\begin{array}{l}{\rightarrow 5 x-x=-1-2 \text { or } x-1=-5 x-2} \\\\ {\rightarrow 4 x=-3 \text { or } 5 x+x=1-2} \\\\ {\rightarrow 4 x=-3 \text { or } 6 x=-1} \\\\ {\rightarrow x=\frac{-3}{4} \text { or } x=\frac{-1}{6}} \\\\ {\rightarrow x=\frac{-3}{4} \text { or } \frac{-1}{6}}\end{array}[/tex]
In options we have only [tex]x = \frac{-1}{6}[/tex]
Hence, the value of x is [tex]\frac{-1}{6}[/tex] and option c is correct