what was the initial temperature is 250 calories reply .1 kg of gold the final temperature of the gold was 175°c ? the specific heat cold is 0.175 °c​

Respuesta :

Answer:

[tex]115.2^{\circ}C[/tex]

Explanation:

When an amount of energy Q is supplied to a substance of mass m, the temperature of the substance increases by [tex]\Delta T[/tex], according to the equation

[tex]Q=mC_s \Delta T[/tex]

where [tex]C_s[/tex] is the specific heat capacity of the substance.

In this problem, we have:

[tex]Q=250 \cdot 4.184 =1046 J[/tex] is the amount of heat supplied to the sample of gold

m = 0.1 kg = 100 g is the mass of the sample

[tex]C_s = 0.175 J/gC[/tex] is the specific heat capacity of gold

Solving for [tex]\Delta T[/tex], we find the change in temperature

[tex]\Delta T = \frac{Q}{m C_s}=\frac{1046}{(100)(0.175)}=59.8^{\circ}[/tex]

And since the final temperature was

[tex]T_f = 175^{\circ}[/tex]

The initial temperature was

[tex]T_i = T_f - \Delta T= 175 -59.8=115.2^{\circ}C[/tex]

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