Answer:
[tex]115.2^{\circ}C[/tex]
Explanation:
When an amount of energy Q is supplied to a substance of mass m, the temperature of the substance increases by [tex]\Delta T[/tex], according to the equation
[tex]Q=mC_s \Delta T[/tex]
where [tex]C_s[/tex] is the specific heat capacity of the substance.
In this problem, we have:
[tex]Q=250 \cdot 4.184 =1046 J[/tex] is the amount of heat supplied to the sample of gold
m = 0.1 kg = 100 g is the mass of the sample
[tex]C_s = 0.175 J/gC[/tex] is the specific heat capacity of gold
Solving for [tex]\Delta T[/tex], we find the change in temperature
[tex]\Delta T = \frac{Q}{m C_s}=\frac{1046}{(100)(0.175)}=59.8^{\circ}[/tex]
And since the final temperature was
[tex]T_f = 175^{\circ}[/tex]
The initial temperature was
[tex]T_i = T_f - \Delta T= 175 -59.8=115.2^{\circ}C[/tex]