Question

Consider the following balanced equation CaC2(s) + 2H2O(I) → Ca(OH)2(s) + C2H2(g)
When 1.50 mol of CaC2 are allowed to react, how many moles of Ca(OH)2 is
produced?​

Answer 1

Answer:

1.50 moles of  CaC₂ will produced 1.50 moles of Ca(OH)₂ .

Explanation:

Given data:

Moles of CaC₂ = 1.50 mol

Moles of Ca(OH)₂ = ?

Solution:

First of all we will write the balanced chemical equation.

CaC₂  + 2H₂O   →  Ca(OH)₂ + C₂H₂

Now we will compare the moles of CaC₂  with Ca(OH)₂ from balanced chemical equation.

                       CaC₂      :       Ca(OH)₂

                        1            :           1

                       1.50       :          1.50

1.50 moles of  CaC₂ will produced 1.50 moles of Ca(OH)₂ .