Answer:
w = -3.8KJ
Explanation:
The work done on a system which is under an external pressure
P = [tex]w = - \int\limits^._. {p} \, dV \\w = - PΔV\\\\[/tex]
P = 1.5 atm
ΔV = 40 − 15 = 25 L
w = - P ΔV = -1.5 (25) = - 37.5 L.atm
w = 37.5 X 101.325 J ≈ − 3800 J = −3.8 KJ