Question

Compressed air is used to fire a 50 gram ball vertically from a 1-meter tube. The air exerts an upward force of 2 N on the ball as long as it in the tube. How high does the ball go above the top of the tube?

Answer 1

Answer:

Height, h = 4.08 meters        

Explanation:

It is given that,

Mass of the ball, m = 50 gram = 0.05 kg

Length of the tube, l = 1 m

Applied force to the ball, F = 2 N

We need to find the the height reached by the ball above the top of the tube. It can be calculated using work energy theorem as :

$F.l=mgh$

$h=\dfrac{Fl}{mg}$

$h=\dfrac{2\times 1}{0.05\times 9.8}$

h = 4.08 meters

So, the the height reached by the ball above the top of the tube is 4.08 meters. Hence, this is the required solution.