Answer: The temperature in the pressure cooker set on high is 250.71°C
Explanation:
STP conditions:
Pressure = 14.7 psi
Temperature = 273 K
To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas.
[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas.
We are given:
[tex]P_1=14.7psi\\T_1=273K\\P_2=(14.7+13.5)psi=28.2psi\\T_2=?[/tex]
Putting values in above equation, we get:
[tex]\frac{14.7psi}{273K}=\frac{28.2psi}{T_2}\\\\T_2=\frac{28.2\times 273}{14.7}=523.71K[/tex]
Converting the temperature from kelvins to degree Celsius, by using the conversion factor:
[tex]T(K)=T(^oC)+273[/tex]
[tex]523.71=T(^oC)+273\\T(^oC)=(523.71-273)K=250.71^oC[/tex]
Hence, the temperature in the pressure cooker set on high is 250.71°C