Answer:
It decreases by a factor of 4
Explanation:
The gravitational force between two masses is given by
[tex]F=\frac{Gm_1 m_2}{r^2}[/tex]
where
G is the gravitational constant
m1, m2 are the two masses
r is the separation between the two masses
In this problem, the distance between the masses is doubled, so
r' = 2r
Substituting into the equation, we see that the new force is
[tex]F'=\frac{Gm_1 m_2}{(2r)^2}=\frac{1}{4}\frac{Gm_1m_2}{r^2})\frac{F}{4}[/tex]
So, the force decreases by a factor of 4.