Question

What is the internal energy of 3.00 mol of Nz gas at 25°C?

Answer 1

Answer:

$1.86\cdot 10^4 J$

Explanation:

I assume you mean $N_2$, which is a diatomic gas.

For a diatomic gas, the internal energy is given by

$U=\frac{5}{2}nRT$

where

n is the number of moles

R is the gas constant

T is the absolute temperature

Here we have:

n = 3.00 mol

$R=8.314 J/(mol K)$

$T=25^{\circ} +273=298 K$

Substituting into the equation, we find the gas internal energy:

$U=\frac{5}{2}(3.00)(8.314)(298)=1.86\cdot 10^4 J$