Question

Three students are discussing a situation where a bicyclist travels at a steady 18.0 m/s for 10 minutes, then at 6.0 m/s for 20 minutes and finally at 12.0 m/s for 15 minutes along a straight level road. Students make the following contentions about the bicyclist's average speed for the overall trip:

Answer 1

Answer:10.667 m/s

Explanation:

Given

For First half students travel for 18 m/s for 10 min

For second half students travel for 6 m/s for 20 min

For last half students travel for 12 m/s for 15 min

average Speed$=\frac{Distance}{Time}$

$V_{avg}=\frac{18\times 600+6\times 1200+12\times 900}{600+1200+900}$

$V_{avg}=\frac{28800}{2700}=10.667$