Question

A bike rider accelerates from + 8 m/s to a velocity of +18 m/s. The bike’s displacement is +14.7 m. What was the total time?

Answer 1

Answer:

1.13 s

Explanation:

We can assume that the motion of the rider is a uniformly accelerated motion, therefore we can solve the problem by using the following suvat equation:

$s=(\frac{u+v}{2})t$

where

s is the displacement

u is the initial velocity

v is the final velocity

t is the time

In this problem,

s = +14.7 m

u = +8 m/s

v = +18 m/s

Solving the formula for t, we find:

$t=\frac{2s}{u+v}=\frac{2(14.7)}{8+18}=1.13 s$