$2000 was borrowed for 4 years with an interest rate of 3% compounded annually. What is the total amount owed at the end of the 4 years.

Answer:
[tex]\$2,251.02[/tex]
Step-by-step explanation:
we know that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where
A is the total amount owed
P is the amount of money borrowed
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
[tex]t=4\ years\\ P=\$2,000\\ r=3\%=3/100=0.03\\n=1[/tex]
substitute in the formula above
[tex]A=2,000*(1+\frac{0.03}{1})^{1*4}[/tex]
[tex]A=2,000*(1.03)^{4}[/tex]
[tex]A=\$2,251.02[/tex]
$2,251.02
Given:
Question:
What is the total amount owed at the end of the 4 years?
The Process:
Compound interest is the interest earned from the initial amount and the interest earned previously. The formula for the balance A of the loan with compound interest is
[tex]\boxed{ \ A = P(1 + \frac{r}{n})^{nt} \ }[/tex]
For interest compounded yearly, we can substitute 1 for n in the formula.
Let us calculate how much the total amount owed at the end of the 4 years.
[tex]\boxed{ \ A = 2,000(1 + 0.03)^{4} \ }[/tex]
[tex]\boxed{ \ A = 2,000(1.03)^{4} \ }[/tex]
[tex]\boxed{ \ A = 2,000 \times 1.12550881 \ }[/tex]
[tex]\boxed{ \ A = 2,251.01762 \ } \rightarrow \boxed{ \ M \approx 2,251.02 \ }[/tex]
Thus, the total amount owed at the end of the four years is $2,251.02.
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Notes
What if the interest rate of 3% is compounded monthly (n = 12)?
[tex]\boxed{ \ A = 2,000(1 + \frac{0.03}{12})^{12 \times 4} \ }[/tex]
[tex]\boxed{ \ A = 2,000(1.0025)^{48} \ }[/tex]
[tex]\boxed{ \ A = 2,000 \times 1.127328021 \ }[/tex]
[tex]\boxed{ \ A = 2,254.656042 \ } \rightarrow \boxed{ \ M \approx 2,254.66 \ }[/tex]
[tex]\boxed{\boxed{ \ M = \$ 2,254.66 \ }}[/tex]
Keywords: $2000, borrowed, for 4 years, with, an interest rate, 3%, 0.03, compounded annually, what is the total amount owed at the end of the 4 years