Question

write an explict equation of how a computer at 2500$ depricates at the rate of 14% per year​

Answer 1

Answer:

V(t)  = 2500(0.86)^t  where t = the year.

Step-by-step explanation:

Each year the  value will be 100 - 14 = 86% ( - 0.86) of the previous year.