29-10-2019
Chemistry

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What quantity of aluminium is deposited when a current of 10A is passed through a solution of aluminium salt for 1930s? (All=27,F=96500cmol)

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kevin900924 kevin900924

29-10-2019

Answer:

AL*3+ + 3e- =AL.

（10A×1930）÷96500=0.2mole e-

0.2÷3×27=1.8g（AL）

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