Answer:
The vertex is (3,-25)
Step-by-step explanation:
Quadratic Function has the form:
[tex]f(x)=ax^2+bx+c[/tex]
Lets use distributive property [a(b+c)=ab+ac] to make the equation given into the vertex form. Thus, we have:
[tex]f(x)=(x-8)(x+2)\\f(x)=x^2+2x-8x-16\\f(x)=x^2-6x-16[/tex]
Thus,
a = 1
b = -6
c = -16
The x coordinate of vertex is given as:
[tex]x=-\frac{b}{2a}[/tex]
Putting the points, we have:
[tex]x=-\frac{-6}{2(1)}=3[/tex]
Putting x = 3 into the function, we get y-value of vertex:
[tex]f(x)=(x-8)(x+2)\\f(x)=(3-8)(3+2)\\f(x)=(-5)(5)\\f(x)=-25[/tex]
The vertex is (3,-25)