Explanation:
It is known that relation between force, mass, velocity and radius is as follows.
F = [tex]\frac{mv^{2}}{r}[/tex]
As diameter is given as 0.20 km. So, radius is [tex]\frac{diameter}{2}[/tex]. Hence, radius will be equal to 0.10 km.
As, 1 km = 1000 m. Therefore, 0.10 km = 100 m.
Also, it is given that mass is 1000 kg and velocity is 30 m/s. Hence, calculate the force required to keep the car from sliding will be as follows.
F = [tex]\frac{mv^{2}}{r}[/tex]
= [tex]\frac{1000 kg \times (30)^{2}}{100 m}[/tex]
= 9000 N
Thus, we can conclude that the magnitude of the friction force required to keep the car from sliding is 9000 N.
The frictional force required to keep the car from sliding is 9,000 N.
The given parameters;
mass of the car, m = 1000 kg
velocity of the car, u = 30 m/s
diameter of the curve, d = 0.2 km = 200 m
radius of the curve, r = 100 m
The frictional force required to keep the car from sliding is the centripetal force keeping the car moving without sliding.
The frictional force required to keep the car from sliding is calculated as follows;
[tex]F_c = \frac{mv^2}{r} \\\\F_c = \frac{1000 \times 30^2 }{100} \\\\F_c = 9,000 \ N[/tex]
Thus, the frictional force required to keep the car from sliding is 9,000 N.
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