11. A carousel has a diameter of 50 feet. To the nearest foot, how far does a child

seated near the outer edge travel when the carousel makes 8

revolutions?

Respuesta :

Answer:

1256 ft

Step-by-step explanation:

The circumference of a circle tell us how long is the line which enclose the circle. So, after 1 revolution a child  seated near the outer edge travels a distance equal to the circumference of the carousel. If 8 revolutions are made the distance travelled will be 8 times the circumference.

Circumference = π · diameter = π · 50 ft = 157 ft

Distance travelled  = 8 · 157 ft = 1256 ft

The distance travelled by the child is 1256 feet.

What is the distance travelled by the child?

The first step is to determine the circumference of the carousel. A carousel has the shape of a circle. So, the formula for the cirucmference of a circle would be used.

Cirucmference of a circle = πD

3.14 x 50 = 157

Now multiply the circumference by 8

157 x 8 = 1256 feet

To learn more about how to determine the circumference of a circle, please check: https://brainly.com/question/14351152

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