Answer:
0.1864 < p < 0.2215
Explanation:
To calculate and construct the 95% confidence interval for the population proportion, it's necessary to use the normal distribution of one sample proportion.
Excel function of normal distribution NORMINV() ---> value of confidence coefficient.
[tex]\\ p = \frac{x}{n}p = \frac{412}{2020\\}\\ \\p = 0.204\\\\\\p +/- z_{0.05/2} X \sqrt{\frac{p (1-p)}{n} }
Excel function:
NORMINV (0.05/2,0,1)
\\\\z_{0.05} = 1.96\\ \\0.204 +/- 1.96 X \sqrt{\frac{0.204 (1-0,204}{2020} }\\ \\0.1864 < p < 0.2215[/tex]