Question

One number exceeds another by 6 .the sum of the numbers is 40. What are the numbers?

Answer 1

Answer:

Let 'another number' be X

Let 'one number' be x+6

X+X+6=72

2X+6=72

2X=66

X=33

'Another number'=33

'One number'=39

Answer 2

1.)Make into equation: X+X+6=40
2.)Combine like terms: 2x+6=40
3.)Simplify: X=17

X=17