Consider a population consisting of the number of teachers per college at small 2-year colleges. Suppose that the number of teachers per college has an average μ = 150 and a standard deviation σ = 20.

a. Use Chebyshev's Rule to make a statement about the minimum percentage of colleges that have between 90 and 210 teachers. (Round your answer to two decimal places if necessary.)

(b) Assume that the population is mound-shaped symmetrical. What proportion of colleges have less than 170 teachers?

Respuesta :

Answer:

a) [tex]\frac{8}{9}[/tex] =0.89

b) 0.8413

Step-by-step explanation:

we know that

[tex]P(║ x -\mu║ \leq  k\sigma) \geq 1 -\frac{1}{k^2}[/tex]

[tex]so, \mu = 150, \sigma = 20[/tex]

[tex]k =  \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3[/tex]

[tex]P(║ x -150 ║ \leq  3\times 20) \geq 1 -\frac{1}{3^2} = \frac{8}{9}[/tex]

x - N(150, 20^2)

[tex]P(X \leq 170) = 0.8413447[/tex]

check

[tex]P norm = \frac{170 - 150}{20}= 0.8413447[/tex]

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