Answer:
Velocity of the electron in the beam.
Radius of the circulating electrons due to the magnetic field.
Explanation:
We have a Mathematical expression for the force on a moving charge in a magnetic field as:
[tex]F=q.v.B.sin \theta[/tex] ...........................(1)
where:
q= charge on the particle in coulomb
v= velocity of the charge projected into the magnetic field
B= intensity of the magnetic field in tesla
[tex] \theta[/tex]= angle between the velocity and direction of magnetic field
For the forces on rotating mass we have the formula:
[tex]F=m.\frac{v^2}{r}[/tex]..........................................(2)
where:
m= mass of the charged particle
v= velocity of projection of charge into the magnetic field
r= radius of the path traced by the charge in the magnetic field
From eq. (1) and (2) we can calculate the magnetic field .
Now,
Using Ampere's Law we have:
[tex]B = \frac{\mu_0 .I}{2 \pi r}[/tex]
where:
I= current in the wire
[tex]\mu_0=[/tex] The permeability of free space.
r= radial distance from the current carrying wire( in this case it is same as the radius of the circular path)