Question

The crate is at rest on the incline. What can you say about the force of friction acting on the crate?

Answer 1

Answer:

$F_f = mg sin\theta$

Explanation:

When a crate is placed on the inclined plane at rest then all the forces on the crate must be balanced

So we can say that force normal to the inclined plane is balanced due to component of the weight

so it is given as

$F_n = mg cos\theta$

here we know that

m = mass of the crate

$\theta$ = angle of inclination of the inclined plane

now along the inclined plane we will say

$F_f = mg sin\theta$

another component of the weight will be balanced by the friction force on the crate

Answer 2

Answer:

The crate accelerates in the same direction as the applied force.

The more force and the longer it’s applied, the greater the velocity when released.

The force disappears when you release the crate, but the crate keeps sliding at a constant velocity.

Explanation:

Plato/Edmentum