Question

A sample of water is heated from 10.0°C to 15.0°C by the addition of 125 J of heat. What is the
mass of the water?​

Answer 1

Answer:

5.97 g of water

Explanation:

• Quantity of heat is given by multiplying the mass of a substance by specific heat capacity then by change in temperature.

Q = m × c × ΔT

In this case;

Quantity of heat, Q = 125 Joules

Change in temperature = 15°C - 10°C

                                       = 5°C

We know that the specific heat capacity of water is 4.186 J/g°C

Therefore, to get the mass we first rearrange the formula;

Mass = Q ÷ cΔT

        = 125 J ÷ (5°C × 4.186 J/g°C)

        = 5.97 g

Therefore, the mass of water is 5.97 g

Answer 2

The mass of a sample of water that is heated from 10.0°C to 15.0°C is 0.00595 kilograms.

Given the following data:

• Initial temperature = 10.0°C

• Final temperature = 15.0°C

• Quantity of heat = 125 Joules

We know that the specific heat capacity of water is 4200 J/kg°C.

To find the  mass of the water:

Mathematically, quantity of heat is given by the formula;

$Q = mc\theta$

Where:

• Q represents the quantity of heat.

• m represents the mass of an object.

• c represents the specific heat capacity.

• ∅ represents the change in temperature.

$\theta = T_2 - T_1\\\\\theta = 15.0 - 10.0\\\\\theta = 5.0$

Making mass the subject of formula, we have:

$Mass = \frac{Q}{c\theta}$

Substituting into the formula, we have:

$Mass = \frac{125}{4200(5)}\\\\Mass = \frac{125}{21000}$

Mass = 0.00595 kilograms

Therefore, the  mass of the water is 0.00595 kilograms.

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